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question:Write a Python solution to generate permutations using backtracking algorithm in lexicographic order.
answer:Here is a Python solution to generate permutations using a backtracking algorithm in lexicographic order: ```python def permute(s): s = sorted(s) # sort the string to get lexicographic order result = [] backtrack(result, [], s) return result def backtrack(result, current, remaining): if not remaining: result.append(''.join(current)) for i in range(len(remaining)): current.append(remaining[i]) backtrack(result, current, remaining[:i] + remaining[i+1:]) current.pop() # backtrack def main(): s = abc permutations = permute(s) for perm in permutations: print(perm) if __name__ == __main__: main() ``` However, the above approach still requires sorting the output to achieve lexicographic order when duplicates exist in the string. Here is an advanced version of the algorithm where the permutations are generated in lexicographic order without the need to sort the final output. ```python def permute(s): s = sorted(s) # sort the string to get lexicographic order result = [] used = [False]*len(s) backtrack(result, [], s, used) return result def backtrack(result, current, s, used): if len(current) == len(s): result.append(''.join(current)) for i in range(len(s)): if used[i] or (i > 0 and s[i] == s[i-1] and not used[i-1]): continue used[i] = True current.append(s[i]) backtrack(result, current, s, used) used[i] = False current.pop() # backtrack def main(): s = abc permutations = permute(s) for perm in permutations: print(perm) if __name__ == __main__: main() ``` This version skips duplicate permutations by checking if the current character is equal to the previous one and if the previous one has not been used yet. If this condition is true, it skips the current character to avoid duplicate permutations.
question:Write the C++ code that would produce the same results as the Python program which generates all permutations of the characters of an input string.
answer:Here is the C++ code that generates all permutations of the characters of an input string using a backtracking algorithm in lexicographic order: ```cpp #include <iostream> #include <algorithm> #include <string> using namespace std; void backtrack(string& s, int start, int end) { if (start == end) { cout << s << endl; } for (int i = start; i <= end; i++) { swap(s[start], s[i]); backtrack(s, start + 1, end); swap(s[start], s[i]); // backtrack } } void permute(string s) { sort(s.begin(), s.end()); // sort the string to get lexicographic order backtrack(s, 0, s.length() - 1); } int main() { string s = abc; permute(s); return 0; } ``` However, the above approach still requires sorting the output to achieve lexicographic order when duplicates exist in the string. Here is an advanced version of the algorithm where the permutations are generated in lexicographic order without the need to sort the final output. ```cpp #include <iostream> #include <algorithm> #include <string> using namespace std; void backtrack(string& s, int start, int end, bool* used) { if (start == end) { cout << s << endl; } for (int i = start; i <= end; i++) { if (used[i] || (i > start && s[i] == s[i-1] && !used[i-1])) { continue; } swap(s[start], s[i]); used[i] = true; backtrack(s, start + 1, end, used); used[i] = false; swap(s[start], s[i]); // backtrack } } void permute(string s) { sort(s.begin(), s.end()); // sort the string to get lexicographic order bool used[s.length()] = {false}; backtrack(s, 0, s.length() - 1, used); } int main() { string s = abc; permute(s); return 0; } ``` This version skips duplicate permutations by checking if the current character is equal to the previous one and if the previous one has not been used yet. If this condition is true, it skips the current character to avoid duplicate permutations.
question:A Canadian Forces crew calmly plucked a terrified crane operator trapped by a smoke-spewing fire in Kingston, Ontario. The Tuesday rescue was captured by television cameras and bystanders and posted to social media. The operator had moved from the cab of his crane to its very tip to escape flames and smoke from a building fire that broke out below him Tuesday, and bystanders captured the rescue in a series of images posted to social media. At first he was petrified, he didn't want to let go of the crane, rescue helicopter commander Capt. David Agnew told CNN affiliate CTV of the crane operator. The helicopter crew arrived to find smoke and flames everywhere and were concerned about the crane collapsing, Agnew told the network. A rescue specialist dropped out of the hovering helicopter on a line, secured the crane operator to himself before the air crew hoisted both back inside to safety. The crane operator suffered only minor injuries, according to CTV. The crane remained standing Wednesday, CBC reported, but engineers are concerned it could fall. A two-block area around the crane remained evacuated, the network said. The fire destroyed a student residence hall being built at Queens University, CBC reported.
answer:A Canadian Forces helicopter crew successfully rescued a crane operator trapped by a fire in Kingston, Ontario, on Tuesday. The operator, initially terrified and clinging to the tip of the crane to escape the smoke and flames, was eventually secured by a rescue specialist and hoisted to safety. Capt. David Agnew, the rescue helicopter commander, noted the crew's concern about the crane collapsing. The crane operator sustained only minor injuries. The fire, which destroyed a student residence hall under construction at Queen's University, prompted the evacuation of a two-block area. Engineers remain concerned about the stability of the crane, which is still standing.
question:You are an AI assistant specialized in generating ideas and facilitating creative thinking can you provide some ideas for A cute and silly magical pet which isn't a cat.
answer:Let's imagine a magical pet that brings a smile to everyone's face. How about a creature that's a cross between a rabbit and a cloud? This fluffy being, which we can call a Flumplen, has the soft, cuddly body of a rabbit but is made entirely out of wispy, white clouds. It has big, shiny eyes that change color depending on its mood and can float around, leaving a trail of sparkles wherever it goes. The Flumplen loves to play hide-and-seek among the clouds, and its favorite game is to transform into a big, puffy cloud and then suddenly pop back into its rabbit-like form, surprising its owner with a joyful Boo! It has the magical ability to make anyone who hugs it feel instantly happy and relaxed, making it the perfect pet for people who need a little stress relief. Alternatively, we could create a magical pet that's inspired by the natural world. Imagine a tiny, mischievous creature that's a combination of a dragonfly and a fairy. This Glimmerwings has iridescent wings that reflect the colors of the rainbow and can fly around its owner's head, creating a dazzling display of light and color. The Glimmerwings has the ability to grant its owner temporary glimpses into the future, but only in a playful, cryptic way. For example, it might leave a trail of glitter that spells out a mysterious message or create a miniature whirlwind that blows away a piece of paper with a hidden message. Its owner has to decipher the clues to figure out what the Glimmerwings is trying to say. Another idea could be a magical pet that's inspired by the world of music. Let's imagine a creature that's a cross between a fox and a musical instrument, like a lyre or a harp. This Melodokit has a beautiful, melodious voice and can play enchanting music on its instrument-like body. The Melodokit has the magical ability to sense its owner's emotions and play music that matches their mood. If its owner is feeling sad, the Melodokit will play a soothing lullaby; if they're feeling energetic, it will play an upbeat dance tune. Its music has the power to heal emotional wounds and bring people together, making it a beloved companion for anyone who loves music. Which of these ideas sparks your imagination?