answer:A: Absolutely! On iOS devices, the Color Filters setting includes several options to assist users with different types of colorblindness: 1. Grayscale: This removes all color from the screen. 2. Protanopia: This is for users who have difficulty distinguishing between red and green. 3. Deuteranopia: This is also a filter for red-green color blindness, but of a different type than Protanopia. 4. Tritanopia: This is for users who have problems distinguishing between blue and yellow. 5. Color Tint: This uniformly applies a color tint to your screen. You can select the one that suits your specific type of color blindness. If you are unsure about which type of color blindness you have, you can experiment with the different modes to see which one works best for you.

answer:A: Certainly! Here are some third-party apps that are designed to assist with colorblindness: 1. Color Blind Pal: This app can help you identify colors and has a color adjustment feature to assist with viewing images and videos. 2. DanKam: This is another color-adjustment app that's designed to help with colorblindness. 3. Chromatic Vision Simulator: This app simulates different types of colorblindness, which could be helpful for adjusting colors in images or when choosing a color palette. Remember to read the reviews and check the compatibility of these apps with your device before downloading.

answer:During the historic Apollo 8 mission, the courageous crew members, comprising of the highly skilled command module pilot William Anders, accompanied by the diligent commander Frank Borman, embarked on a groundbreaking journey to orbit the moon, cementing their names in the annals of space exploration and etching Apollo 8's legacy into humanity's collective memory.

answer:To solve the problem that the proposition ax^{2}-2ax+3 > 0 always holds is false, it means that There exists x in mathbb{R} such that ax^{2}-2ax+3 leqslant 0 holds is a true proposition (1). When a=0, proposition (1) does not hold. When a neq 0, for (1) to hold, it must be that a < 0 or begin{cases} text{for } a > 0, & 4a^{2}-12a geqslant 0 end{cases}, Therefore, a < 0 or a geqslant 3. Hence, the answer is: (-infty,0) cup [3, +infty). By transforming the condition into There exists x in mathbb{R} such that ax^{2}-2ax+3 leqslant 0 holds, we examine whether a=0 satisfies the condition. When a neq 0, it must be that a < 0 or begin{cases} text{for } a > 0, & 4a^{2}-12a geqslant 0 end{cases}, thereby solving the range of real numbers for a. This problem examines the application of quadratic inequalities, emphasizing the connection to the characteristics of the corresponding quadratic function's graph, reflecting the mathematical ideas of equivalent transformation and case discussion. Therefore, the range of values for a is boxed{(-infty,0) cup [3, +infty)}.